You may be one click away from a better job!  
Let Recruiter sift through 6 million jobs daily and tell you about new opportunities in your area.  
Create a new job alert today, and be the first to know about new local openings in your field of interest  
Do it once,and you`re done!  
SAMPLE JOB FOR THE KEYWORD “MANAGER”. CLICK TO CUSTOMIZE THE JOB AND LOCATION  


EDIT MY JOB ALERT 

Top 10  Get Hired  Inside Recruiting 
The Innovators  Success  Smart Tech 



TELL A FRIEND 
This email has been sent to you because you are a member of Recruiter.com.
Want to receive our newsletter daily, weekly or not at all? Change your newsletter settings here, or unsubscribe.
Do not reply to this email. If this email looks suspicious in any way, do not respond or perform any requested action. Recruiter will never request you to share your password or personal information in an email. Contact us with any issues.
Recruiter.com, Inc. © 2017  1533 New Britain Avenue, Second Floor, Farmington, CT 06032
To: EMyrone@aol.com
Sent: 27/06/2017 18:36:37 GMT Daylight Time
Subj: Re: Solution for Spin ConnectionThis sounds interesting, then we have to compute bold B from the standing wave to see how this situation can be realized.
Horst
Am 27.06.2017 um 14:13 schrieb EMyrone:
I have solved Eqs. (16) to (23) by hand to find a standing wave solution for the Q vector. The spin connection in this case is the simple omega bold = kappa and omega sub zero = omega, so the spin connection is the four wave vector. The general solution can be found by computer and this does not look to be a difficult problem. This is well worth doing because the method gives the spin connection four vector and the kappa vector in a perfectly general way.
To: EMyrone@aol.com
Sent: 27/06/2017 18:28:33 GMT Daylight Time
Subj: Re: Discussion of 380(4)When inserting eqs. (10,11) into (9), I obtain the equation
curl ( omega sub 0 Q) – partial / partial t (omega x Q) = 0
which gives a sign change when moving the second term to the RHS.
Horst
Am 27.06.2017 um 10:16 schrieb EMyrone:
I think that Eq. (13) is OK, because it is derived from
curl ( omega sub 0 Q) = – partial / partial t (omega x Q)
To: EMyrone
Sent: 26/06/2017 15:44:41 GMT Daylight Time
Subj: Re Re: Discussion of 380(4)Shouldn’t there be a minus sign in eq.(13)?
Horst
Am 26.06.2017 um 16:20 schrieb Horst Eckardt:
It seems that in eqs.(1618) of the note the dime derivatives at the LHS are missing.
Horst
Am 26.06.2017 um 09:56 schrieb EMyrone:
Agreed entirely. Eqs. (16) to (23) make up the set of simultaneous spatial equations in three dimensions, and can be solved for the Q three vector and spin connection four vector in general, for any situation in gravitation and electrodynamics, and combination therefore. In electrodynamics they can be used to solve for the A threevector and the spin connection fourvector in general. I gradually worked towards this new general solution in the four notes. This is equivalent to a general solution of the EEC2 field equations in three dimensions. So we can now address any problem in physics, chemistry and engineering. Guesswork is no longer needed for the spin connection. In this set of equations there are only space variables, and I think that the computer can deal with the problem of solving a set of seven, fairly simple, simultaneous partial differential equations in seven unknowns, the three scalar components of Q or A and the four components of the spin connection. The general solution can be simplified, and any coordinates can be used, not only the Cartesain. However the Cartesain is the clearest as you inferred some time ago. The Eckardt / Lindstrom methods can be added to this new method. The solutions will almost certainly produce some very interesting spatial graphics. Having found omega sub X and onega sub Y from this genreal method, one can go back to teh orbital equations to see qhat kind of orbits emeerge, and one can addres the Biefeld Brown effect in a self consistent way. Finally, Q or A is also time dependent: Q = Q (t, X, Y, Z); A = A(t, X, Y, Z). An example is plane waves. The scalar potential is also t and space dependent in general.
To: EMyrone
Sent: 25/06/2017 15:55:21 GMT Daylight Time
Subj: Re: 380(4): Compleet Solution in Three dimensions.It is not se easy to find a set of equations which can give well defined field solutions. For example there must be time and space derivatives for each variable to give unique solutions. The Lagrangian seems mainly to be used to obtain time trajectories of orbits but not for general field solutions. In so far I am not sure if it makes sense to use the LHS of eq.(3) for determining distributed fields Phi and bold omega.
Eqs.(1623) is a more general scheme which seems to fulfill the above condition. For a solution, the boundary conditions are essential, because there are no terms of inhomogeneity like a charge density.Horst
Am 25.06.2017 um 10:25 schrieb EMyrone:
This note derives a completely general set of seven simultaneous differential equations, (16) – (18), (19) – (21) and (23) for seven unknowns, the three Cartesian components of the Q threevector and the four components of the spin connection fourvector. These can all be expressed as functions of space and time. This is an exactly determined problem in three dimensions. The method uses the two homogeneous field equations of ECE2 gravitation, Eq. (22) and the Faraday law of induction Eq. (9), and the antisymmetry condition (19) to (21). In two dimensions X and Y, there is only one antisymmetry condition (27) and the Faraday law reduces to Eq. (28). Using the Coulomb law of ECE2 gravitation gives Eq. (36). So in the planar limit thee are three equations in five unknowns. The Newtonian limit of Eqs. (30) and (31) is used to give five equations in five unknowns. In the next note the Ampere Maxwell Law of ECE2 gravitation will be introduced into the planar analysis, to seek a general solution without having to assume the Newtonian approximation.
This server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials (e.g., bad password), or your browser doesn’t understand how to supply the credentials required.
Additionally, a 401 Unauthorized error was encountered while trying to use an ErrorDocument to handle the request.
To: EMyrone@aol.com
Sent: 26/06/2017 20:00:53 GMT Daylight Time
Subj: Re: Another suggestion for solving the antigravity problemA simple solution could be looking as follows:
The gravitational acceleration isg = – nabla Phi + bold omega * Phi
with spin connection omega and gravitational potential Phi. Since there is only one space geometry, there is only one and the same omega for gravitation and electromagnetism. If it is possible to enhance bold omega significantly by electromagnetism, this should have an impact on g. So one of the equations (the above one) is nearly trivial. The question is how to construct an additional bold omega by electromagnetism. My idea was by a rotating magnetic field. But how to compute this? We need a quantitative theory.
Horst
Am 26.06.2017 um 10:11 schrieb EMyrone:
Agreed with this, Note 380(4) can be appleid to this anti gravity problem in order to simulate the apparatus and optimize conditions for counter gravitation. Note 380(4) used the homogeneous field equations of ECE2 gravitation:
del cap omega = 0
curl g + partial cap omega / partial t = 0
and the antisymmetry laws from
cap omega = curl Q – omega x Q
Here cap omega is the gravitomagnetic field, g is the gravitational field, Q is the gravitational vector potential, and omega the space part of the spin connection four vector. The inhomogeneous laws of ECE2 gravitation were not used in Note 380(4), and it was shown that the above three equations are sufficient to completely determine Q and the spin connection four vector. Having found them, they can be used in the inhomogeneous laws, the ECE2 gravitational Coulomb law and Ampere Maxwell law. Exactly the same remarks apply to ECE2 electromagnetism, and combinations of electromagnetism and gravitation. This ought to produce efficient counter gravitational designs. We can describe any existing counter gravitational apparatus with these powerful ECE2 equations.
To: EMyrone
Sent: 25/06/2017 16:01:12 GMT Daylight Time
Subj: Another suggestion for solving the antigravity problemThere are rumours out that antigravity can be achieved by rotating
magnetic fields (like in a 3phase motor). In this case the spin
connection is the vector of the rotation axis if I see this right. So we
have a predefined bold omega and can apply the Faraday and/or
AmpereMaxwell law to find bold A and bold Q. Perhaps worth a thought. I
am not sure if the coupling from em to gravity can be applied in the
same way as before.Horst
curl ( omega sub 0 Q) = – partial / partial t (omega x Q)
To: EMyrone@aol.com
Sent: 26/06/2017 15:44:41 GMT Daylight Time
Subj: Re Re: Discussion of 380(4)Shouldn’t there be a minus sign in eq.(13)?
Horst
Am 26.06.2017 um 16:20 schrieb Horst Eckardt:
It seems that in eqs.(1618) of the note the dime derivatives at the LHS are missing.
Horst
Am 26.06.2017 um 09:56 schrieb EMyrone:
Agreed entirely. Eqs. (16) to (23) make up the set of simultaneous spatial equations in three dimensions, and can be solved for the Q three vector and spin connection four vector in general, for any situation in gravitation and electrodynamics, and combination therefore. In electrodynamics they can be used to solve for the A threevector and the spin connection fourvector in general. I gradually worked towards this new general solution in the four notes. This is equivalent to a general solution of the EEC2 field equations in three dimensions. So we can now address any problem in physics, chemistry and engineering. Guesswork is no longer needed for the spin connection. In this set of equations there are only space variables, and I think that the computer can deal with the problem of solving a set of seven, fairly simple, simultaneous partial differential equations in seven unknowns, the three scalar components of Q or A and the four components of the spin connection. The general solution can be simplified, and any coordinates can be used, not only the Cartesain. However the Cartesain is the clearest as you inferred some time ago. The Eckardt / Lindstrom methods can be added to this new method. The solutions will almost certainly produce some very interesting spatial graphics. Having found omega sub X and onega sub Y from this genreal method, one can go back to teh orbital equations to see qhat kind of orbits emeerge, and one can addres the Biefeld Brown effect in a self consistent way. Finally, Q or A is also time dependent: Q = Q (t, X, Y, Z); A = A(t, X, Y, Z). An example is plane waves. The scalar potential is also t and space dependent in general.
To: EMyrone
Sent: 25/06/2017 15:55:21 GMT Daylight Time
Subj: Re: 380(4): Compleet Solution in Three dimensions.It is not se easy to find a set of equations which can give well defined field solutions. For example there must be time and space derivatives for each variable to give unique solutions. The Lagrangian seems mainly to be used to obtain time trajectories of orbits but not for general field solutions. In so far I am not sure if it makes sense to use the LHS of eq.(3) for determining distributed fields Phi and bold omega.
Eqs.(1623) is a more general scheme which seems to fulfill the above condition. For a solution, the boundary conditions are essential, because there are no terms of inhomogeneity like a charge density.Horst
Am 25.06.2017 um 10:25 schrieb EMyrone:
This note derives a completely general set of seven simultaneous differential equations, (16) – (18), (19) – (21) and (23) for seven unknowns, the three Cartesian components of the Q threevector and the four components of the spin connection fourvector. These can all be expressed as functions of space and time. This is an exactly determined problem in three dimensions. The method uses the two homogeneous field equations of ECE2 gravitation, Eq. (22) and the Faraday law of induction Eq. (9), and the antisymmetry condition (19) to (21). In two dimensions X and Y, there is only one antisymmetry condition (27) and the Faraday law reduces to Eq. (28). Using the Coulomb law of ECE2 gravitation gives Eq. (36). So in the planar limit thee are three equations in five unknowns. The Newtonian limit of Eqs. (30) and (31) is used to give five equations in five unknowns. In the next note the Ampere Maxwell Law of ECE2 gravitation will be introduced into the planar analysis, to seek a general solution without having to assume the Newtonian approximation.
To: EMyrone@aol.com
Sent: 26/06/2017 15:19:53 GMT Daylight Time
Subj: Re: Discussion of 380(4)It seems that in eqs.(1618) of the note the dime derivatives at the LHS are missing.
Horst
Am 26.06.2017 um 09:56 schrieb EMyrone:
Agreed entirely. Eqs. (16) to (23) make up the set of simultaneous spatial equations in three dimensions, and can be solved for the Q three vector and spin connection four vector in general, for any situation in gravitation and electrodynamics, and combination therefore. In electrodynamics they can be used to solve for the A threevector and the spin connection fourvector in general. I gradually worked towards this new general solution in the four notes. This is equivalent to a general solution of the EEC2 field equations in three dimensions. So we can now address any problem in physics, chemistry and engineering. Guesswork is no longer needed for the spin connection. In this set of equations there are only space variables, and I think that the computer can deal with the problem of solving a set of seven, fairly simple, simultaneous partial differential equations in seven unknowns, the three scalar components of Q or A and the four components of the spin connection. The general solution can be simplified, and any coordinates can be used, not only the Cartesain. However the Cartesain is the clearest as you inferred some time ago. The Eckardt / Lindstrom methods can be added to this new method. The solutions will almost certainly produce some very interesting spatial graphics. Having found omega sub X and onega sub Y from this genreal method, one can go back to teh orbital equations to see qhat kind of orbits emeerge, and one can addres the Biefeld Brown effect in a self consistent way. Finally, Q or A is also time dependent: Q = Q (t, X, Y, Z); A = A(t, X, Y, Z). An example is plane waves. The scalar potential is also t and space dependent in general.
To: EMyrone
Sent: 25/06/2017 15:55:21 GMT Daylight Time
Subj: Re: 380(4): Compleet Solution in Three dimensions.It is not se easy to find a set of equations which can give well defined field solutions. For example there must be time and space derivatives for each variable to give unique solutions. The Lagrangian seems mainly to be used to obtain time trajectories of orbits but not for general field solutions. In so far I am not sure if it makes sense to use the LHS of eq.(3) for determining distributed fields Phi and bold omega.
Eqs.(1623) is a more general scheme which seems to fulfill the above condition. For a solution, the boundary conditions are essential, because there are no terms of inhomogeneity like a charge density.Horst
Am 25.06.2017 um 10:25 schrieb EMyrone:
This note derives a completely general set of seven simultaneous differential equations, (16) – (18), (19) – (21) and (23) for seven unknowns, the three Cartesian components of the Q threevector and the four components of the spin connection fourvector. These can all be expressed as functions of space and time. This is an exactly determined problem in three dimensions. The method uses the two homogeneous field equations of ECE2 gravitation, Eq. (22) and the Faraday law of induction Eq. (9), and the antisymmetry condition (19) to (21). In two dimensions X and Y, there is only one antisymmetry condition (27) and the Faraday law reduces to Eq. (28). Using the Coulomb law of ECE2 gravitation gives Eq. (36). So in the planar limit thee are three equations in five unknowns. The Newtonian limit of Eqs. (30) and (31) is used to give five equations in five unknowns. In the next note the Ampere Maxwell Law of ECE2 gravitation will be introduced into the planar analysis, to seek a general solution without having to assume the Newtonian approximation.
This server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials (e.g., bad password), or your browser doesn’t understand how to supply the credentials required.
Additionally, a 401 Unauthorized error was encountered while trying to use an ErrorDocument to handle the request.
To: emyrone@aol.com, mail@horsteckardt.de
Sent: 26/06/2017 06:04:56 GMT Daylight Time
Subj: Re: Discussion of 380(2): Combined Gravitation and Electromagnetism, Biefeld BrownMy point was not about photons being changed in mass but in trajectory.
For example a laser maybe useful in an experiment to measure electrogravitic effects due to light bending.Sean
On June 23, 2017 at 1:37:34 AM, emyrone@aol.com (emyrone) wrote:
The photon is not charged, but in previous UFT papers and in ECE2 (UFT366) the ECE2 theory of light bending by gravitation is given.
Sent: 22/06/2017 20:33:49 GMT Daylight Time
Subj: Re: 380(2): Combined Gravitation and Electromagnetism, Biefeld BrownIf a local gravitational field can be altered by an electric potential can the path of light be warped as means of detection of the gravitational bending?
Sean
On June 21, 2017 at 5:40:42 AM, emyrone@aol.com (emyrone) wrote:
This note gives a scheme of computation on page 7 by which the problem can be solved completely and in general. There are enough equations to find all the unknowns, given of course the skilful use of the computer by co author Horst Eckardt. The Biefeld Brown effect is explained straightforwardly by Eq. (14), which shows that an electric charge density can affect the gravitational scalar potential and therefore can affect g. I did a lit search on the Biefeld Brown effect, it has recently been studied by the U. S. Army Research Laboratory. This report can be found by googling Biefeld Brown effect”, site four. There are various configuration which can all be explained by Eq. (14) – asymmetric electrodes and so on. In the inverse r limit the total potential energy is given by Eq. (19). This gives the planar orbital equations on page 4 of the Note. These can be solved numerically to give some very interesting orbits using the methods of UFT378. The lagrangian in this limit is Eq. (29) and the hamiltonian is Eq. (30). These describe the orbit of a mass m and charge e1 around a mass M and charge e2. If Sommerfeld quantization is applied this method gives the Sommerfeld atom. Otherwise in the classical limit it desribes the orbit of one charge with mass around another. The equations are given in a plane but can easily be extended to three dimensions. Eqs. (31) to (34), solved simultaneously and numerically with Eqs. ((37) and (39), the antisymmetry conditions, are six equations in six unknowns for gravitation and six equations in six unknowns for electromagnetism. These equations give the spin connections and vector potentials in general (three Cartesian components each).