## Another suggestion for solving the antigravity problem

I agree that the spin connection vector omega bold is a universal geometrical property that is the same for electromagnetism and gravitation. So is omega sub 0. The rigorous answer is to solve Eqs. (16) to (23) of Note 280(4) for bold Q, bold omega, and omega sub 0, then find phi for gravitation from Eq. (10) of that note. Finally use Eq. (14) of Note 380(2) to find the electric charge density needed to cahnge the gravitational phi to any desired value. Alternatively find bold omega from solving Eqs. (16) to (23) simultaneously, then use a model charge density in Eq. (14) to find phi. These are only two out of many possibilities. The set of Eqs. (16) to (23) can be simplified by intelligent approximation. I will think about this next. The give the gravitational vector potential Q (t, X, Y, Z) in a completely general way.

To: EMyrone@aol.com

Sent: 26/06/2017 20:00:53 GMT Daylight Time

Subj: Re: Another suggestion for solving the antigravity problemA simple solution could be looking as follows:

The gravitational acceleration isg = – nabla Phi + bold omega * Phi

with spin connection omega and gravitational potential Phi. Since there is only one space geometry, there is only one and the same omega for gravitation and electromagnetism. If it is possible to enhance bold omega significantly by electromagnetism, this should have an impact on g. So one of the equations (the above one) is nearly trivial. The question is how to construct an additional bold omega by electromagnetism. My idea was by a rotating magnetic field. But how to compute this? We need a quantitative theory.

Horst

Am 26.06.2017 um 10:11 schrieb EMyrone:

Agreed with this, Note 380(4) can be appleid to this anti gravity problem in order to simulate the apparatus and optimize conditions for counter gravitation. Note 380(4) used the homogeneous field equations of ECE2 gravitation:

del cap omega = 0

curl g + partial cap omega / partial t = 0

and the antisymmetry laws from

cap omega = curl Q – omega x Q

Here cap omega is the gravitomagnetic field, g is the gravitational field, Q is the gravitational vector potential, and omega the space part of the spin connection four vector. The inhomogeneous laws of ECE2 gravitation were not used in Note 380(4), and it was shown that the above three equations are sufficient to completely determine Q and the spin connection four vector. Having found them, they can be used in the inhomogeneous laws, the ECE2 gravitational Coulomb law and Ampere Maxwell law. Exactly the same remarks apply to ECE2 electromagnetism, and combinations of electromagnetism and gravitation. This ought to produce efficient counter gravitational designs. We can describe any existing counter gravitational apparatus with these powerful ECE2 equations.

To: EMyrone

Sent: 25/06/2017 16:01:12 GMT Daylight Time

Subj: Another suggestion for solving the antigravity problemThere are rumours out that antigravity can be achieved by rotating

magnetic fields (like in a 3-phase motor). In this case the spin

connection is the vector of the rotation axis if I see this right. So we

have a predefined bold omega and can apply the Faraday and/or

Ampere-Maxwell law to find bold A and bold Q. Perhaps worth a thought. I

am not sure if the coupling from e-m to gravity can be applied in the

same way as before.Horst

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